The Date object will do what you want – construct one for each date, then compare them using the >, <, <= or >=. The ==, !=, ===, and !== operators require you to use date.getTime() as in var d1 = new Date(); var d2 = new Date(d1); var same = d1.getTime() === d2.getTime(); var … Read more
You could use Enumerable.SequenceEqual. This works for any IEnumerable<T>, not just arrays.
Order of operations causes (0 < 5 < 3) to be interpreted in javascript as ((0 < 5) < 3) which produces (true < 3) and true is counted as 1, causing it to return true. This is also why (0 < 5 < 1) returns false, (0 < 5) returns true, which is interpreted … Read more
JavaScript is very flexible with regards to checking for “null” values. I’m guessing you’re actually looking for empty strings, in which case this simpler code will work: if(!pass || !cpass || !email || !cemail || !user){ Which will check for empty strings (“”), null, undefined, false and the numbers 0 and NaN. Please note that … Read more
I wrote a little class that is doing what you want, you can test it here. Only thing that is different from your proposal is that I don’t consider [1,[{c: 1},2,3],{a:’hey’}] and [{a:’hey’},1,[3,{c: 1},2]] to be same, because I think that arrays are not equal if order of their elements is not same. Of course … Read more
sqldf provides a nice solution a1 <- data.frame(a = 1:5, b=letters[1:5]) a2 <- data.frame(a = 1:3, b=letters[1:3]) require(sqldf) a1NotIna2 <- sqldf(‘SELECT * FROM a1 EXCEPT SELECT * FROM a2’) And the rows which are in both data frames: a1Ina2 <- sqldf(‘SELECT * FROM a1 INTERSECT SELECT * FROM a2’) The new version of dplyr has … Read more
This is problem: if [[$variable == $blanko]]; Spaces are required inside square brackets, use it like this: [[ “$variable” == “$blanko” ]] && echo “Nichts da!” || echo “$variable”
Because, as in many programming languages, strings are compared lexicographically. You can think of this as a fancier version of alphabetical ordering, the difference being that alphabetic ordering only covers the 26 characters a through z. This answer is in response to a java question, but the logic is exactly the same. Another good one: … Read more
If all your dates are posterior to the 1st of January of 1970, you could use something like: $today = date(“Y-m-d”); $expire = $row->expireDate; //from database $today_time = strtotime($today); $expire_time = strtotime($expire); if ($expire_time < $today_time) { /* do Something */ } If you are using PHP 5 >= 5.2.0, you could use the DateTime … Read more
The exception message is actually pretty descriptive. The contract it mentions is transitivity: if A > B and B > C then for any A, B and C: A > C. I checked it with paper and pencil and your code seems to have few holes: if (card1.getRarity() < card2.getRarity()) { return 1; you do … Read more