Solution: I put all of the conditional statements inside of if (!allCorrect[i]) so it looks like this if (!allCorrect[i]) { if (int.TryParse(parameters[i], out INT)) { if (_command.ParameterTypes[i] == EVariableType.INT) { allCorrect[i] = true; } else { allCorrect[i] = false; } } } if (!allCorrect[i]) { if (float.TryParse(parameters[i], out FLOAT)) { if (_command.ParameterTypes[i] == EVariableType.FLOAT) { … Read more
In your second code block you are first checking if the first character is the same as the last. If it isn’t, return false. Else, return true. So this isn’t going to be a valid palindrome check. It only checks if the first and last letters are the same or not and ignores the letters … Read more
I do not know whether this solution is more efficient, but maybe it is more readable and easier to code: #include <iostream> #include <cstdlib> int main() { const int magicNumber = 32640; const int maxOffset = 1920; int n; std::cin >> n; int y = 20; const std::div_t divresult = std::div(n, magicNumber); if (divresult.rem > … Read more
You can work something out using lambda’s, but it will not be a clean syntax: return (chkStatus ? (Func<object>)(() => { DoLog(cmd.CommandText); return obj; }) : () => null)();