How to initialize a const field in constructor?
You need to do it in an initializer list: Bar(Foo* _foo) : foo(_foo) { } (Note that I renamed the incoming variable to avoid confusion.)
You need to do it in an initializer list: Bar(Foo* _foo) : foo(_foo) { } (Note that I renamed the incoming variable to avoid confusion.)
How can I do what I want to do (that is, initialize an array in a constructor (not assigning elements in the body)). Is it even possible? Yes. It’s using a struct that contains an array. You say you already know about that, but then I don’t understand the question. That way, you do initialize … Read more
This is a member initializer list, and is part of the constructor’s implementation. The constructor’s signature is: MyClass(); This means that the constructor can be called with no parameters. This makes it a default constructor, i.e., one which will be called by default when you write MyClass someObject;. The part : m_classID(-1), m_userdata(0) is called … Read more
Only local const references prolong the lifespan. The standard specifies such behavior in ยง8.5.3/5, [dcl.init.ref], the section on initializers of reference declarations. The reference in your example is bound to the constructor’s argument n, and becomes invalid when the object n is bound to goes out of scope. The lifetime extension is not transitive through … Read more
Foo(int num): bar(num) This construct is called a Member Initializer List in C++. Simply said, it initializes your member bar to a value num. What is the difference between Initializing and Assignment inside a constructor? Member Initialization: Foo(int num): bar(num) {}; Member Assignment: Foo(int num) { bar = num; } There is a significant difference … Read more