With moment.js you can create a moment object using the String+Format constructor: var momentDate = moment(‘2015-01-16 22:15:00’, ‘YYYY-MM-DD HH:mm:ss’); Then, you can convert it to JavaScript Date Object using toDate() method: var jsDate = momentDate.toDate();
You are calling the following method. public static OffsetDateTime parse(CharSequence text) { return parse(text, DateTimeFormatter.ISO_OFFSET_DATE_TIME); } It uses uses DateTimeFormatter.ISO_OFFSET_DATE_TIME as DateTimeFormatter which, as stated in the javadoc, does the following: The ISO date-time formatter that formats or parses a date-time with an offset, such as ‘2011-12-03T10:15:30+01:00’. If you want to parse a date with … Read more
DateTimeFormatter dtf = DateTimeFormatter.ofPattern(“uuuu-MM-dd H:mm:ss”); With this change your program outputs: 2019-05-03T07:05:03 A single format pattern letter H will match hour of day in either 1 or two digits. That is, it will accept 7, 07, 13, etc. Two HH on the other hand requires two digits like 07 or 13, so 7 alone cannot … Read more
The devil is in the detail. You are basically doing it correctly, except: You need to provide a locale for the formatter. By parsing into a LocalDateTime you are losing information and possibly getting an unexpected result. So I suggest: DateTimeFormatter formatter = DateTimeFormatter.ofPattern( “EEE MMM dd HH:mm:ss zzz yyyy”, Locale.ROOT); String linesplit8 = “Wed … Read more
You have to use the formatter when parsing the date string. Also you need to tell it to change the zone or zone offset to get it into AEST/AEDT. This might work: DateTimeFormatter dtf = DateTimeFormatter.ofPattern(“yyyy-MM-dd’T’HH:mm:ss.SSSXX”); ZonedDateTime zdt = OffsetDateTime.parse(input, dtf) .atZoneSameInstant(ZoneId.of(“Australia/Sydney”)); String dateInTimeZone = zdt.format(dtf); The offset will appear as “+1000” or “+1100” depending … Read more
Date date = new Date(); DateFormat dateFormat = new SimpleDateFormat(“yyyy-MM-dd’T’HH:mm:ss.SSSZ”);//2018-02-05T18:00:51.001+0000 String text = dateFormat.format(date); try { Date test = dateFormat.parse(text); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } worked for me. With “SSSZ” instead of “SZ” at the end of the pattern.
Twitter dates in specific are interesting because they are relative only for the first day. After 24 hours they just show the month and day. After a year they start showing the last two digits of the year. Here’s a sample function that does something more akin to Twitter relative dates, though it always shows … Read more
datetime.datetime.strptime has problems with timezone parsing. Have a look at the dateutil package: >>> from dateutil import parser >>> parser.parse(“Tue May 08 15:14:45 +0800 2012”) datetime.datetime(2012, 5, 8, 15, 14, 45, tzinfo=tzoffset(None, 28800))
std::tm tm = {}; std::stringstream ss(“Jan 9 2014 12:35:34”); ss >> std::get_time(&tm, “%b %d %Y %H:%M:%S”); auto tp = std::chrono::system_clock::from_time_t(std::mktime(&tm)); GCC prior to version 5 doesn’t implement std::get_time. You should also be able to write: std::tm tm = {}; strptime(“Thu Jan 9 2014 12:35:34”, “%a %b %d %Y %H:%M:%S”, &tm); auto tp = std::chrono::system_clock::from_time_t(std::mktime(&tm));
If you want to parse all valid formats of offsets (Z, ±hh:mm, ±hhmm and ±hh), one alternative is to use a java.time.format.DateTimeFormatterBuilder with optional patterns (unfortunatelly, it seems that there’s no single pattern letter to match them all): DateTimeFormatter formatter = new DateTimeFormatterBuilder() // date/time .append(DateTimeFormatter.ISO_LOCAL_DATE_TIME) // offset (hh:mm – “+00:00” when it’s zero) .optionalStart().appendOffset(“+HH:MM”, … Read more