Another answer because this is very different from my previous answer, and this is blazing fast. Relative error is 3e-8. Want more accuracy? Add a couple more Chebychev terms. It’s best to keep the order odd as this makes for a small discontinuity between 2^n-epsilon and 2^n+epsilon. #include <stdlib.h> #include <math.h> // Returns x^(5/12) for … Read more
There is a no way to control that, best way is to write a function for this e.g. def eformat(f, prec, exp_digits): s = “%.*e”%(prec, f) mantissa, exp = s.split(‘e’) # add 1 to digits as 1 is taken by sign +/- return “%se%+0*d”%(mantissa, exp_digits+1, int(exp)) print eformat(0.0000870927939438012, 14, 3) print eformat(1.0000870927939438012e5, 14, 3) print … Read more
So you want to translate SI unit abbreviations (‘K’,’M’,…) into exponents, and thus numerical powers-of-ten. Given that all units are single-letter, and the exponents are uniformly-spaced powers of 10**3, here’s working code that handles ‘Kilo’…’Yotta’, and any future exponents: > 10 ** (3*as.integer(regexpr(‘T’, ‘KMGTPEY’))) [1] 1e+12 Then just multiply that power-of-ten by the decimal value … Read more
The C# language doesn’t have a power operator. However, the .NET Framework offers the Math.Pow method: Returns a specified number raised to the specified power. So your example would look like this: float Result, Number1, Number2; Number1 = 2; Number2 = 2; Result = Math.Pow(Number1, Number2);
Operator ^ is a bitwise operator, which does bitwise exclusive or. The power operator is **, like 8**3 which equals to 512.
It is a floating point number, you have to tell it that: decimal d = Decimal.Parse(“1.2345E-02”, System.Globalization.NumberStyles.Float);