It is simple: Address = Address.concat(String.valueOf(i)); Address initailly had a whatever value: 5.20.86.0. In your for loop you are appending the i current value, but you don’t delete the previous value! So it is going to 5.20.86.012345678910 as 5.20.86. and 012345678910 than 012345678910 11 12 13 14 and so on. I hope it is a … Read more
Try this. I think you should recalculate the total money. Because number of shops is 21, is correct. Please recalculate total money; it can never be 210000. public class investmentCalculation { private int income; private int shop; private int firstMoney; private int totalMoney1; private int shopsAdded; public investmentCalculation() { income = 10000; shop = 3; … Read more
We, beginners, should help each other. If the function deals with strings then the second parameter of the function is redundant. A straightforward approach without using standard containers as for example std::set can look the following way #include <iostream> void missing( const char s[] ) { const char *letter = “abcdefghijklmnopqrstuvwxyz”; for ( size_t i … Read more
Well you can introduce a counter to be sure int counter = 0; for (int i = 0; i < n; i++) for(int j = 0; j < i; j++) { printf(“Hello World”); counter ++; } Or take a pen : i = 1 j = 0 Hello World i = 2 j = 0 … Read more
As simple as that: word = input(“Enter a word: “) print(“***”) for letter in word: print(letter) print(“***”)
I’m guessing what you’re looking for is something similar to this? #include <iostream> using namespace std; int main() { for(int i = 0; i <= 50; ++i) { ((i % 6) == 5) ? cout << i << ‘\n’ : cout << i << ‘ ‘; } return 0; } nested for loop example: #include … Read more
As others have commented you probably have an iterator, not a list; You can use itertools.tee to get two independent iterators from same iterable: >>> from itertools import tee >>> a = [1, 2, 3] >>> fst, snd = tee(iter(a)) # two copies of same iterator >>> >>> list(fst) # exhaust the first iterator [1, … Read more
Try something like this: System.out.println( “Farenheit | Celsius | Kelvin” ); // For loop for ( double f = startfarh ; f <= endfarh ; f += 1d ) { double c = ( f – 32 ) / 1.8d; double k = c + 273.15; System.out.printf( “%7.2f°F = %6.2f°C = %6.2fK%n”, f, c, k … Read more
We need to know what the values of start, end, and step are. if: start = 0; end = 10; step = 1; It would loop 11 times, each time adding 1 to the previous value of i until it is <= 10. (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11) … Read more