The problem is in the condition if((i + j) > ((n / 2) + 1)) It should be if(j >= n – i – 1) // or if(i + j >= n – 1) To make this easier, I would create a helper function. Also, there’s no need for the VLA a[n][n] that you don’t … Read more
You need to have only one for loop: import java.util.Scanner; public class NTC { public static void main(String[] args) { Scanner kb=new Scanner(System.in); int loop = 10; double rate=0; int time=0; int count; double distance = rate*time; System.out.println(“How many times would you like to calculate the distance.”); loop = kb.nextInt(); for (count = 0; count … Read more
You could organize your data as follows: class Program { static void Main(string[] args) { List<Criteria> list = new List<Criteria>() { new Criteria(Color.green, Country.england, Town.london, GoodBad.good, DayOfTheWeek.sunday, Daytime.evening), new Criteria(Color.red, Country.thenetherlands, Town.amsterdam, GoodBad.bad, DayOfTheWeek.monday, Daytime.night), new Criteria(Color.blue, Country.america, Town.newyork, GoodBad.bad, DayOfTheWeek.tuesday, Daytime.morning), }; Console.WriteLine(“- Native sorting:”); list.Sort(); foreach(var criteria in list) { Console.WriteLine(criteria); } Console.WriteLine(); … Read more
In your main method, you can call your methods by using: public static void main(String[] args) { //– Your original code up above printArray(testArray1); //For the array of ints printArray(testArray2); //For the array of doubles }
Dont know what you mean there. But here is what I understand from your question <?php for ($i=0; $i< count($contentdinamit[“chart”][“songs”][“song”]); $i++ ) { if(($i+1)<=10){//limit your item by 10 echo'<li class=”up”><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”><strong>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“song_name”].'</strong></a><br /><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'</a></li>’; } } ?>
Assuming you’re just using lm the trick is to change the data argument to subset to something different. speciesList <- unique(df$Species) for(i in 1:length(speciesList){ lmmodel <- lm(x ~ year, data = subset(df, Species == speciesList[i])) #Now do all the stuff you want with lmmodel, e.g. plot, find slope, etc } I’m not going to write … Read more
Nested for loops like that are used when you have pseudo code like this: Do the following x times: Do the following y times: some stuff Do the following z times: some stuff In your specific case, the size of the pyramid is dynamic and is stored in a variable called size. To print a … Read more
You could do this, but you probably shouldn’t: def forn(n): def new_func(func): for i in range(n): func(i) return func return new_func @forn(10) def f(i): print(i) or this: def forn(n, func) return [func(i) for i in range(n)] x = forn(10, lambda x: x**2) But these are more verbose and less readable than for i in range(10): … Read more
This line: $i = $integer; …is redundant, as soon as you say for($i = …, $i will be overwritten. In your case, so it should be. Take that line out to start with. Second, I think the problem you’re having is that your lines aren’t showing as black or red. Reason is that color is … Read more
try for (int i = 0; i < a.Length; i++) // or i < n if you want { print i; int z = a[i]; // this line will get value from a one by one, 0, 1, 2, 3 and so on… } Edit 1 – After seeing the comments on the other answer, … Read more