Note: The widely used solution above is based on displayMetrics.density. However, the docs explain that this value is a rounded value, used with the screen ‘buckets’. Eg. on my Nexus 10 it returns 2, where the real value would be 298dpi (real) / 160dpi (default) = 1.8625. Depending on your requirements, you might need the … Read more
There’s also exp4j, an expression evaluator based on Dijkstra’s Shunting Yard. It’s freely available and redistributable under the Apache License 2.0, only about 25KB in size, and quite easy to use: Calculable calc = new ExpressionBuilder(“3 * sin(y) – 2 / (x – 2)”) .withVariable(“x”, varX) .withVariable(“y”, varY) .build() double result1=calc.calculate(); When using a newer … Read more
Evaluate might suit: http://www.mrexcel.com/forum/showthread.php?t=62067 Function Eval(Ref As String) Application.Volatile Eval = Evaluate(Ref) End Function
See ?as.formula, e.g.: factors <- c(“factor1”, “factor2”) as.formula(paste(“y~”, paste(factors, collapse=”+”))) # y ~ factor1 + factor2 where factors is a character vector containing the names of the factors you want to use in the model. This you can paste into an lm model, e.g.: set.seed(0) y <- rnorm(100) factor1 <- rep(1:2, each=50) factor2 <- rep(3:4, … Read more
You can use 1) pd.eval(), 2) df.query(), or 3) df.eval(). Their various features and functionality are discussed below. Examples will involve these dataframes (unless otherwise specified). np.random.seed(0) df1 = pd.DataFrame(np.random.choice(10, (5, 4)), columns=list(‘ABCD’)) df2 = pd.DataFrame(np.random.choice(10, (5, 4)), columns=list(‘ABCD’)) df3 = pd.DataFrame(np.random.choice(10, (5, 4)), columns=list(‘ABCD’)) df4 = pd.DataFrame(np.random.choice(10, (5, 4)), columns=list(‘ABCD’)) 1) pandas.eval This is … Read more
your actual goal is unclear you may want to start form this code Sub test() Dim i As Integer For i = 1 To 10 cells(i, 4).Formula = “=Sum(E” & i & “:E15)” Next End Sub and adjust it to your needs, knowing that: it currently writes in cells “D1:D10” since cells(i, 4) references a … Read more
I’m not 100% sure what you are trying to achive. But assuming you are trying to do some sort of compounding interest. This should help. public static void main(String[] args) { double startAmount = 1000; double ratePercentage = 0.05; double newAmount; newAmount = startAmount; for (int i = 0; i <= 10; i++){ newAmount = … Read more
The problem is that the numbers are being calculated to a higher precision. Try, =ABS(ROUND(K2, 2)*(ROUND(K11, 2)-ROUND(K10, 2))/ROUND(K13, 2)) Look into the ‘Precision as displayed’ option but be sure to understand all of the caveats before deciding to do it.
You could take a bitwise AND & with the day value and take this day. const days = { Monday: 1, Tuesday: 2, Wednesday: 4, Thursday: 8, Friday: 16, Saturday: 32, Sunday: 64 }, getDays = value => Object.keys(days).filter(day => value & days[day]); console.log(getDays(127)); // All Days console.log(getDays(80)); // Friday, Sunday console.log(getDays(7)); // Monday, Tuesday, … Read more