Almost. I’d write it like this: public class Pair<F, S> { private F first; //first member of pair private S second; //second member of pair public Pair(F first, S second) { this.first = first; this.second = second; } public void setFirst(F first) { this.first = first; } public void setSecond(S second) { this.second = second; … Read more
You can use num or num-traits crates and bound your generic function type with num::Float, num::Integer or whatever relevant trait: use num::Float; // 0.2.1 fn main() { let f1: f32 = 2.0; let f2: f64 = 3.0; let i1: i32 = 3; println!(“{:?}”, sqrt(f1)); println!(“{:?}”, sqrt(f2)); println!(“{:?}”, sqrt(i1)); // error } fn sqrt<T: Float>(input: T) … Read more
In order to solve this problem with templates, you have to use a template template parameter. Unfortunately, you cannot pass template template function as a type, because it has to be instantiated first. But there is a workaround with dummy structures. Here is an example: template <typename T> struct a { static void foo (T … Read more
The other answers are totally fine: One does not need a special syntax to support generics in Python Python uses duck typing as pointed out by André. However, if you still want a typed variant, there is a built-in solution since Python 3.5. A full list of available type annotations is available in the Python … Read more