Php condition doesn't work for html [closed]
try if($_GET[“menu”] == “mMenu-Point”) : At the moment you are setting (=) $_GET[“menu”] not comparing it (==)
try if($_GET[“menu”] == “mMenu-Point”) : At the moment you are setting (=) $_GET[“menu”] not comparing it (==)
In your code, if (number == 10 || 11 || 12 || 13 || 14 || 15 || 16 || 17 ||18 || 19) is a wrong approach. You cannot chain the logical operator like that. As of now, because of the operator precedence, your code is essentially if ( (number == 10) || 11 … Read more
You could organize your data as follows: class Program { static void Main(string[] args) { List<Criteria> list = new List<Criteria>() { new Criteria(Color.green, Country.england, Town.london, GoodBad.good, DayOfTheWeek.sunday, Daytime.evening), new Criteria(Color.red, Country.thenetherlands, Town.amsterdam, GoodBad.bad, DayOfTheWeek.monday, Daytime.night), new Criteria(Color.blue, Country.america, Town.newyork, GoodBad.bad, DayOfTheWeek.tuesday, Daytime.morning), }; Console.WriteLine(“- Native sorting:”); list.Sort(); foreach(var criteria in list) { Console.WriteLine(criteria); } Console.WriteLine(); … Read more
The wording of your question is difficult to understand, but I think this hint is what you are trying to figure out: if <some condition goes here>: <statements to execute if the statement is true> <something goes here>: <statements to execute if the statement is false> What word goes in place of <something goes here>?
The identation is incorrect and causing the error. Also, the and true does not serve anything there. You can try the following code: a = 200 b = 33 c = 500 if a < b: print(“Both conditions are True”) elif a > b: print(“f”)
Your SQL query/logic is completely wrong. What you should do is check if that user and password combination exits in database using WHERE clause. But actually you are doing is fetching each row and checking for equality. In such situation you can also get n numbers of wrong credentials. $query = mysql_query(“SELECT * FROM table … Read more
if ((dateString = asd)) Here you are assigning asd to dateString, as you use a single =. Comparisons are made with ==. But as NSString instances are pointers, you can’t use == to compare the string values. Use: if( [ str1 isEqualToString: str2 ] ) That being said, I think you should really take some … Read more
Welcome to StackOverflow, At this point I’m assuming you have been rigorously reading all the suggested material pointed out by the fine people that have supplied you with comments to assist you in acquiring the proper help you seek. After all, you haven’t provided a response to some of the valid questions related to your … Read more
You should use if-elif-else statement instead. Currently, your code is performing x = 3 if x == 3: # This will be True, so test = “True” test=”True” if x == 5: # This will be also tested because it is a new if statement. It will return False, so it will enter else statement … Read more
The problem seems to be the for loop. Your program accepts a value for a as an input, but then as soon as the loop begins, it resets the value of a to 0 (for (a = 0;… Therefore it’s looping 10 times, and on each loop a will have a different value, starting from … Read more