In C++11 there are some nice new convert functions from std::string to a number type. So instead of atoi( str.c_str() ) you can use std::stoi( str ) where str is your number as std::string. There are version for all flavours of numbers: long stol(string), float stof(string), double stod(string),… see http://en.cppreference.com/w/cpp/string/basic_string/stol
If you just want to filter everything other than the numbers out, the easiest is to use filter_var: $str=”In My Cart : 11 items”; $int = (int) filter_var($str, FILTER_SANITIZE_NUMBER_INT);
Take a look at PEP-238: Changing the Division Operator The // operator will be available to request floor division unambiguously.
int() is the Python standard built-in function to convert a string into an integer value. You call it with a string containing a number as the argument, and it returns the number converted to an integer: >>> int(“1”) + 1 2 If you know the structure of your list, T1 (that it simply contains lists, … Read more
Generate unique random numbers between 1 and 100
The JVM is caching Integer values. Hence the comparison with == only works for numbers between -128 and 127. Refer: #Immutable_Objects_.2F_Wrapper_Class_Caching
This is a common Javascript gotcha with a simple solution: Just specify the base, or ‘radix’, like so: parseInt(’08’,10); // 8 You could also use Number: Number(’08’); // 8
When you compile a number literal in Java and assign it to a Integer (capital I) the compiler emits: Integer b2 =Integer.valueOf(127) This line of code is also generated when you use autoboxing. valueOf is implemented such that certain numbers are “pooled”, and it returns the same instance for values smaller than 128. From the … Read more
No, == between Integer, Long etc will check for reference equality – i.e. Integer x = …; Integer y = …; System.out.println(x == y); this will check whether x and y refer to the same object rather than equal objects. So Integer x = new Integer(10); Integer y = new Integer(10); System.out.println(x == y); is … Read more
If it overflows, it goes back to the minimum value and continues from there. If it underflows, it goes back to the maximum value and continues from there. You can check that beforehand as follows: public static boolean willAdditionOverflow(int left, int right) { if (right < 0 && right != Integer.MIN_VALUE) { return willSubtractionOverflow(left, -right); … Read more