Next business day of given date in PHP

Next Weekday This finds the next weekday from a specific date (not including Saturday or Sunday): echo date(‘Y-m-d’, strtotime(‘2011-04-05 +1 Weekday’)); You could also do it with a date variable of course: $myDate=”2011-04-05″; echo date(‘Y-m-d’, strtotime($myDate . ‘ +1 Weekday’)); UPDATE: Or, if you have access to PHP’s DateTime class (very likely): $date = new … Read more

Continue For loop

You can use a GoTo: Do ‘… do stuff your loop will be doing ‘ skip to the end of the loop if necessary: If <condition-to-go-to-next-iteration> Then GoTo ContinueLoop ‘… do other stuff if the condition is not met ContinueLoop: Loop

jquery, find next element by class

In this case you need to go up to the <tr> then use .next(), like this: $(obj).closest(‘tr’).next().find(‘.class’); Or if there may be rows in-between without the .class inside, you can use .nextAll(), like this: $(obj).closest(‘tr’).nextAll(‘:has(.class):first’).find(‘.class’);

javascript node.js next()

This appears to be a variable naming convention in Node.js control-flow code, where a reference to the next function to execute is given to a callback for it to kick-off when it’s done. See, for example, the code samples here: http://blog.mixu.net/2011/02/02/essential-node-js-patterns-and-snippets/ Let’s look at the example you posted: function loadUser(req, res, next) { if (req.session.user_id) … Read more

Passing variables to the next middleware using next() in Express.js

This is what the res.locals object is for. Setting variables directly on the request object is not supported or documented. res.locals is guaranteed to hold state over the life of a request. res.locals (Note: the documentation quoted here is now outdated, check the link for the most recent version.) An object that contains response local … Read more

How can I override next() for jagged array java?

This might be a wrong answer to your question. I’ll remove it in that case, but maybe you can use it for what you want to achieve: int[][] it = {{1,2}, {3,4,5}}; OfInt iterator = Arrays.stream(it).flatMapToInt(x -> IntStream.of(x)).iterator(); iterator.forEachRemaining((IntConsumer) System.out::print); Stream the jagged array, flatmap it into one single IntStream and then do what you … Read more