This appears to create an object from an interface; how does it work?
You’re defining an anonymous class that implements the interface Int, and immediately creating an object of type thatAnonymousClassYouJustMade.
You’re defining an anonymous class that implements the interface Int, and immediately creating an object of type thatAnonymousClassYouJustMade.
I think you can use this to copy the value instead of the reference: var b = a.slice(0); EDIT As the comments have mentioned and it’s also mentioned here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/slice slice does not alter the original array, but returns a new “one level deep” copy that contains copies of the elements sliced from the original … Read more
Typically, a Json object would contain your values (including arrays) as named fields within. So, something like: JSONObject jo = new JSONObject(); JSONArray ja = new JSONArray(); // populate the array jo.put(“arrayName”,ja); Which in JSON will be {“arrayName”:[…]}.
Converts Array of objects into Array of Arrays: var outputData = inputData.map( Object.values );
A category can not declare additional instance variables but since OS X 10.6 and iOS 3.1 you can work around this with associative references. You can use associative references to simulate the addition of object instance variables to an existing class. Using associative references, you can add storage to an object without modifying the class … Read more
This will work: echo $object->feed->{‘xmlns$media’}; Alternatively, you can tell json_decode to return an array: $array = json_decode($json, true); echo $array[‘feed’][‘xmlns$media’];
You can override operator>> and operator<< to read/write to stream. Example Entry struct with some values: struct Entry2 { string original; string currency; Entry2() {} Entry2(string& in); Entry2(string& original, string& currency) : original(original), currency(currency) {} }; istream& operator>>(istream& is, Entry2& en); ostream& operator<<(ostream& os, const Entry2& en); Implementation: using namespace std; istream& operator>>(istream& is, Entry2& … Read more
Since the common ancestor of your classes is Object, and because List<? extends Object> does not make things any cleaner (after all, everything extends Object) it looks like List<Object> would be an OK choice. However, such list would be a mixed bag: you would need to check run-time type of the object inside, and make … Read more
Java works a little bit different than many other languages. What o is in the first example is simply a reference to the object. When you say o = new MyObject(), it creates a new Object of type MyObject and references o to that object, whereas before o referenced objects[index]. That is, objects[index] itself is … Read more
Use get_class to get the class name of an object.