Disabled elements do not fire events, e.g. users cannot hover or click them to trigger a popover (or tooltip). You can however wrap the disabled element with a DIV and listen to the event fired on that element instead.
As the function name suggests getElementsByClassName returns a collection not just one object. So you need to loop through them and apply the color to it. document.getElementsByClassName() ^_______ Plus your id part is invalid. Id cannot have spaces and also it shouldn’t appear again on the page which is violated by: <th id=”colorswitcher A” onmouseover=”document.getElementsByClassName(‘a’).style.background=’red'”>a</th> … Read more
const mouseoverEvent = new Event(‘mouseover’); whateverElement.dispatchEvent(mouseoverEvent);
Are you looking for something like this perhaps? To show popup over selected row(s) only private void maybeShowPopup(MouseEvent e) { if (e.isPopupTrigger()) { // get row that pointer is over int row = table.rowAtPoint(e.getPoint()); // if pointer is over a selected row, show popup if (table.isRowSelected(row)) { popup.show(e.getComponent(), e.getX(), e.getY()); } } } Or the … Read more
Like this ? Example.. (Just edit your element selector, if you know jQuery enough) HTML : <ul> <li>Menu#1</li> <span>Sub</span> <li>Menu#2</li> <span>Sub</span> </ul> jQuery : $(“ul li”).click(function () { $(this).addClass(“showing”).next(“span”).show(); }); $(‘ul’).mouseout(function() { $(“ul li.showing”).removeClass().next(“span”).hide(); }); Demo : http://jsfiddle.net/JcKxV/ Edited in your case… Gonna look like.. $(“#theme_select”).click(function() { if (theme_list_open == false) { $(“.center ul li … Read more