I am not going to give you exact code but I will give you some links that will help you. strchr :: You can use this find the position of ‘=’ in the string. Now, copy the string after the position of ‘=’ till you find a ‘space’. Whenever you will find a ‘space’, write … Read more
You’re completely missing the point of String.format. The point of it is to avoid manually formatting and concatenating strings representing elements, which you are doing anyway. Since if (num1 == 24 && num2 == 00) must be true to be in that if block you can simply System.out.println(“24 00 Midnight”);.
There are some facts about c you’re missing: There’s no string datatype. A string is just a sequence of char ending with a 0 byte. What you use here is a string literal — the compiler translates it to an array of char and automatically adds the 0 at the end. An array when passed … Read more
The error is that %d in the format specifier of both scanf and printf represents decimal, so it expects an int (in the case of scanf, a pointer to int) Since you are declaring b and c as float, %d in the lines scanf(“%d”,&b); printf(“%d lbs is %d kgs.”,b,c); should be changed to %f respectively. … Read more
Actually % is not the modulo operand or modulo operator here because it’s included inside a string. It’s just a character chosen to separate literal text from parameters. And d is used because it performs input and output in decimal (base 10).
In order to print decimals (easily), you need floating point: printf(“%10.6f”, static_cast<double>(1) / 3); If one of the arguments to division is floating point, the compiler will promote the expression to floating point. Integral or scalar division will lose decimals. You are always welcome to write your own division function. Edit 1: Shifting You don’t … Read more
%x format specifier experts the argument to be of type unsigned int. In your case, printf(“%x\n”,(const uint8_t)0x0D); printf(“%x\n”,0x0D); arguments will be promoted (default promotion rule) to match the type, but in case of printf(“%x\n”,(const uint8_t *)0x0D); //supplying a pointer printf(“%x\n”,(uint8_t *)0x0D); //supplying a pointer You’ll invoke undefined behavior, as per C11, chapter ยง7.21.6.1 […] If … Read more
printf returns: On success, the total number of characters written. On failure, a negative number.
void correct(r) is declaration and it means – correct is a function that takes r type in arguments and returns void. Just remove void to call function. correct(r). And you need to change chars to char * or const char*. const char *c1 = “Cristoforo”; const char *c2 = “cristoforo”; const char *c3 = “CRISTOFORO”;
Actually printf is used in java if you are using formatting as he was asking about in his question. double number = 10.5555555; System.out.printf(“The number 10.555555 rounded to two decimal places is %2f”, number); Now as far as the symbols, the ones I know are %d = integer, %f= double, %s= string.