I asked the question long time ago, so I might be wrong in some details. It turns out that Blob needs array buffers. That’s why base64 bytes need to be converted to array buffers first. Here is the function to do that: function base64ToArrayBuffer(base64) { var binaryString = window.atob(base64); var binaryLen = binaryString.length; var bytes … Read more
1- Go to flutter\bin\cache and remove a file named: flutter_tools.stamp 2- Go to flutter\packages\flutter_tools\lib\src\web and open the file chrome.dart. 3- Find ‘–disable-extensions’ 4- Add ‘–disable-web-security’
With Tomcat 7, you can add the StuckThreadDetectionValve which will enable you to identify threads that are “stuck”. You can set-up the valve in the Context element of the applications where you want to do detecting: <Context …> … <Valve className=”org.apache.catalina.valves.StuckThreadDetectionValve” threshold=”60″ /> … </Context> This would write a WARN entry into the tomcat log … Read more
OK, after a lot of digging, I found out that requestSettings should have: encoding: null And then body will be of type Buffer, instead of the default, which is string.
Pragma is the HTTP/1.0 implementation and cache-control is the HTTP/1.1 implementation of the same concept. They both are meant to prevent the client from caching the response. Older clients may not support HTTP/1.1 which is why that header is still in use.
Edit 2: Release 1.15.2 of the body parser module introduces raw mode, which returns the body as a Buffer. By default, it also automatically handles deflate and gzip decompression. Example usage: var bodyParser = require(‘body-parser’); app.use(bodyParser.raw(options)); app.get(path, function(req, res) { // req.body is a Buffer object }); By default, the options object has the following … Read more
You can observe the full response instead of the content only. To do so, you have to pass observe: response into the options parameter of the function call. http .get<MyJsonData>(‘/data.json’, {observe: ‘response’}) .subscribe(resp => { // Here, resp is of type HttpResponse<MyJsonData>. // You can inspect its headers: console.log(resp.headers.get(‘X-Custom-Header’)); // And access the body directly, … Read more
With jQuery: $.post(“test.php”, { json_string:JSON.stringify({name:”John”, time:”2pm”}) }); Without jQuery: var xmlhttp = new XMLHttpRequest(); // new HttpRequest instance xmlhttp.open(“POST”, “/json-handler”); xmlhttp.setRequestHeader(“Content-Type”, “application/json”); xmlhttp.send(JSON.stringify({name:”John Rambo”, time:”2pm”}));
Note: the following is dangerous, and will allow API content to be intercepted and modified between the client and the server. This also worked process.env[‘NODE_TLS_REJECT_UNAUTHORIZED’] = ‘0’;
Direct answer: you can not do that. PHP insists on parsing it itself, whenever it sees the multipart/form-data Content-Type. The raw data will not be available to you. Sadly. But you can hack around it. I hit a similar problem, a partner was sending incorrectly formatted data as multipart/form-data, PHP could not parse it and … Read more