seq - w3toppers.com

How to produce cartesian product in bash?

Combine two brace expansions! $ printf “%s\n” {1..3}” “{1..5} 1 1 1 2 1 3 1 4 1 5 2 1 2 2 2 3 2 4 2 5 3 1 3 2 3 3 3 4 3 5 This works by using a single brace expansion: $ echo {1..5} 1 2 3 4 5 … Read more

Repeat vector when its length is not a multiple of desired total length

Use the length.out argument of rep() or rep_len (a “faster simplified version” [of rep]): length.out: non-negative integer. The desired length of the output vector Here is an example using the built-in dataset cars. str(cars) ‘data.frame’: 50 obs. of 2 variables: $ speed: num 4 4 7 7 8 9 10 10 10 11 … $ … Read more

Generate an incrementally increasing sequence like 112123123412345

Use sequence: > sequence(1:5) [1] 1 1 2 1 2 3 1 2 3 4 1 2 3 4 5

Select every other element from a vector

remove[c(TRUE, FALSE)] will do the trick. How it works? If logical vectors are used for indexing in R, their values are recycled if the index vector is shorter than the vector containing the values. Here, the vector remove contains ten values. If the index vector c(TRUE, FALSE) is used, the actual command is: remove[c(TRUE, FALSE, … Read more

Create sequence of repeated values, in sequence?

You missed the each= argument to rep(): R> n <- 3 R> rep(1:5, each=n) [1] 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 R> so your example can be done with a simple R> rep(1:8, each=20)

Variables in bash seq replacement ({1..10}) [duplicate]

In bash, brace expansion happens before variable expansion, so this is not directly possible. Instead, use an arithmetic for loop: start=1 end=10 for ((i=start; i<=end; i++)) do echo “i: $i” done OUTPUT i: 1 i: 2 i: 3 i: 4 i: 5 i: 6 i: 7 i: 8 i: 9 i: 10