[*] As most times, the compiler is right and intuition wrong. The problem is that if that particular assignment was allowed you could break const-correctness in your program: const int constant = 10; int *modifier = 0; const int ** const_breaker = &modifier; // [*] this is equivalent to your code *const_breaker = & constant; … Read more
This is not stored as an integer by PHP, but a float, this is why you end up with 1.0E+25 instead of 10000000000000000000000000. It’s sadly not possible to use that as an integer value in PHP, as PHP cannot save an integer of that size. If this comes from database then it will be a … Read more
This answer assumes that float is an IEEE-754 single precision float encoded as 32-bits, and that an int is 32-bits. See this Wikipedia article for more information about IEEE-754. Floating point numbers only have 24-bits of precision, compared with 32-bits for an int. Therefore int values from 0 to 16777215 have an exact representation as … Read more
Try this: double a; memcpy(&a, ptr, sizeof(double)); where ptr is the pointer to your byte array. If you want to avoid copying use a union, e.g. union { double d; char bytes[sizeof(double)]; } u; // Store your data in u.bytes // Use floating point number from u.d
Because a Person is not nessecarily a User, the compiler is not able to implicitly convert a Person to a User. In your particular case, since you know you have a list of Users, you can explicitly tell it, “I know this Person is actually a User” with the following: if (person != null) return … Read more
The cvtsd2ss instruction uses the FPU’s rounding mode to do the conversion. The default rounding mode is round-to-nearest-even. In order to follow the algorithm, it helps to keep in mind the information at the IEEE 754-1985 Wikipedia page, especially the diagrams representing the layout. First, the exponent of the target float is computed: the double … Read more
You can put the variables in an object then easily print them this way: http://jsfiddle.net/5MVde/7/ See fiddle for everything, this is the JavaScript… var x = { foo: 5, bar: 6, foobar: function (){ var that=this; return that.foo+that.bar } }; var myDiv = document.getElementById(“results”); myDiv.innerHTML=’Variable Names…’; for(var variable in x) { //alert(variable); myDiv.innerHTML+='<br>’+variable; } myDiv.innerHTML+='<br><br>And … Read more
Relevant quote from the Standard: 5 Expressions [expr] 10 Many binary operators that expect operands of arithmetic or enumeration type cause conversions and yield result types in a similar way. The purpose is to yield a common type, which is also the type of the result. This pattern is called the usual arithmetic conversions, which … Read more
This is an implementation of Yakk’s second option: template <class… Args> struct variant_cast_proxy { std::variant<Args…> v; template <class… ToArgs> operator std::variant<ToArgs…>() const { return std::visit([](auto&& arg) -> std::variant<ToArgs…> { return arg ; }, v); } }; template <class… Args> auto variant_cast(const std::variant<Args…>& v) -> variant_cast_proxy<Args…> { return {v}; } You might want to fine tune … Read more
You should be able to add your own function to implement this feature. The class would look something like this: namespace MyProject\Query; use Doctrine\ORM\Query\AST\Functions\FunctionNode; use Doctrine\ORM\Query\Lexer; use Doctrine\ORM\Query\Parser; use Doctrine\ORM\Query\SqlWalker; class CastAsInteger extends FunctionNode { public $stringPrimary; public function getSql(SqlWalker $sqlWalker) { return ‘CAST(‘ . $this->stringPrimary->dispatch($sqlWalker) . ‘ AS integer)’; } public function parse(Parser $parser) … Read more