Since Javascript doesn’t have the lookbehind feature and since word boundaries work only with members of the \w character class, the only way is to use groups (and capturing groups if you want to make a replacement): (?m)(^|[^a-zA-ZΆΈ-ώἀ-ῼ\n])([a-zA-ZΆΈ-ώἀ-ῼ]{2})(?![a-zA-ZΆΈ-ώἀ-ῼ]) example to remove 2 letters words: txt = txt.replace(/(^|[^a-zA-ZΆΈ-ώἀ-ῼ\n])([a-zA-ZΆΈ-ώἀ-ῼ]{2})(?![a-zA-ZΆΈ-ώἀ-ῼ])/gm, ‘\1’);
This sounds like a job for lookbehinds, though you should be aware that not all regex flavors support them. In your example: (?<=\bipsum\s)(\w+) This will match any sequence of letter characters which follows “ipsum” as a whole word followed by a space. It does not match “ipsum” itself, you don’t need to worry about reinserting … Read more
Even in UTF-8 mode, standard class shorthands like \w and \b are not Unicode-aware. You just have to use the Unicode shorthands, as you worked out, but you can make it a little less ugly by using lookarounds instead of alternations: /(?<!\pL)weiß(?!\pL)/u Notice also how I left the curly braces out of the Unicode class … Read more
A word boundary (\b) is a zero width match that can match: Between a word character (\w) and a non-word character (\W) or Between a word character and the start or end of the string. In Javascript the definition of \w is [A-Za-z0-9_] and \W is anything else. The negated version of \b, written \B, … Read more
PostgreSQL uses \m, \M, \y and \Y as word boundaries: \m matches only at the beginning of a word \M matches only at the end of a word \y matches only at the beginning or end of a word \Y matches only at a point that is not the beginning or end of a word … Read more
I believe you want to try select 1 from dual where regexp_like (‘does test work here’, ‘(^|\s)test(\s|$)’); because the \b does not appear on this list: Perl-influenced Extensions in Oracle Regular Expressions The \s makes sure that test starts and ends in a whitespace. This is not sufficient, however, since the string test could also … Read more
You may use XRegExp as source of a custom word boundary: function getWholeWords(input, word) { var pL = 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var rx = RegExp(“(?:^|[^_0-9” + pL + “])(” + word + “)(?![_0-9” + pL + “])”, “ig”); // Build the regex (might be moved out from the function) var words = []; while ((m = rx.exec(input)) … Read more
The word boundary assertion does only match if a word character is not preceded or followed by another word character (so .\b. is equal to \W\w and \w\W). And \w is defined as [A-Za-z0-9_]. So \w doesn’t match greek characters. And thus you cannot use \b for this case. What you could do instead is … Read more
Use word boundary \b which matches a between a word and non-word character, string = c(“apple”, “apples”, “applez”) grep(“\\bapple\\b”, string) [1] 1 OR Use anchors. ^ Asserts that we are at the start. $ Asserts that we are at the end. grep(“^apple$”, string) [1] 1 You could store the regex inside a variable and then … Read more
A word boundary, in most regex dialects, is a position between \w and \W (non-word char), or at the beginning or end of a string if it begins or ends (respectively) with a word character ([0-9A-Za-z_]). So, in the string “-12”, it would match before the 1 or after the 2. The dash is not … Read more