Since your config file is a valid shell script, you can source it into your current shell: . config_file echo “Content of VARIABLE1 is $VARIABLE1” echo “Content of VARIABLE2 is $VARIABLE2” echo “Content of VARIABLE3 is $VARIABLE3” Slightly DRYer, but trickier . config_file for var in VARIABLE1 VARIABLE2 VARIABLE3; do echo “Content of $var is … Read more
What he meant is that job control is by default turned off in non-interactive mode (i.e. in a script.) From the bash man page: JOB CONTROL Job control refers to the ability to selectively stop (suspend) the execution of processes and continue (resume) their execution at a later point. A user typically employs this facility … Read more
You have to resort to dirty tricks: #!/bin/bash # based on a script from http://invisible-island.net/xterm/xterm.faq.html exec < /dev/tty oldstty=$(stty -g) stty raw -echo min 0 # on my system, the following line can be replaced by the line below it echo -en “\033[6n” > /dev/tty # tput u7 > /dev/tty # when TERM=xterm (and relatives) … Read more
From grep –help, but also see man grep: Exit status is 0 if any line was selected, 1 otherwise; if any error occurs and -q was not given, the exit status is 2. if grep –quiet MYSQL_ROLE=master /etc/aws/hosts.conf; then echo exists else echo not found fi You may want to use a more specific regex, … Read more
You can use backslash for line continuation. However note that the shell receives the whole command concatenated into a single line, so you also need to terminate some of the lines with a semicolon: foo: for i in `find`; \ do \ all=”$$all $$i”; \ done; \ gcc $$all But if you just want to … Read more
Does your script reference /bin/bash or /bin/sh in its hash bang line? The default system shell in Ubuntu is dash, not bash, so if you have #!/bin/sh then your script will be using a different shell than you expect. Dash does not have the <<< redirection operator. Make sure the shebang line is: #!/bin/bash or … Read more
Summary Inserting \n p=”${var1}\n${var2}” echo -e “${p}” Inserting a new line in the source code p=”${var1} ${var2}” echo “${p}” Using $’\n’ (only Bash and Z shell) p=”${var1}”$’\n'”${var2}” echo “${p}” Details Inserting \n p=”${var1}\n${var2}” echo -e “${p}” echo -e interprets the two characters “\n” as a new line. var=”a b c” first_loop=true for i in $var … Read more
You should add quotes and also, your function declaration is wrong. myFunction() { echo “$1” echo “$2” echo “$3” } And like the others, it works for me as well.
These are positional arguments of the script. Executing ./script.sh Hello World Will make $0 = ./script.sh $1 = Hello $2 = World Note If you execute ./script.sh, $0 will give output ./script.sh but if you execute it with bash script.sh it will give output script.sh.
Answer cat testfile | awk ‘{ print length, $0 }’ | sort -n -s | cut -d” ” -f2- Or, to do your original (perhaps unintentional) sub-sorting of any equal-length lines: cat testfile | awk ‘{ print length, $0 }’ | sort -n | cut -d” ” -f2- In both cases, we have solved your … Read more