Trying to embed newline in a variable in Bash [duplicate]

Summary

  1. Inserting \n

     p="${var1}\n${var2}"
     echo -e "${p}"
    
  2. Inserting a new line in the source code

     p="${var1}
     ${var2}"
     echo "${p}"
    
  3. Using $'\n' (only Bash and Z shell)

     p="${var1}"$'\n'"${var2}"
     echo "${p}"
    

Details

  1. Inserting \n

     p="${var1}\n${var2}"
     echo -e "${p}"
    

    echo -e interprets the two characters "\n" as a new line.

     var="a b c"
     first_loop=true
     for i in $var
     do
        p="$p\n$i"            # Append
        unset first_loop
     done
     echo -e "$p"             # Use -e
    

    Avoid extra leading newline

     var="a b c"
     first_loop=1
     for i in $var
     do
        (( $first_loop )) &&  # "((...))" is bash specific
        p="$i"            ||  # First -> Set
        p="$p\n$i"            # After -> Append
        unset first_loop
     done
     echo -e "$p"             # Use -e
    

    Using a function

     embed_newline()
     {
        local p="$1"
        shift
        for i in "$@"
        do
           p="$p\n$i"         # Append
        done
        echo -e "$p"          # Use -e
     }
    
     var="a b c"
     p=$( embed_newline $var )  # Do not use double quotes "$var"
     echo "$p"
    
  2. Inserting a new line in the source code

     var="a b c"
     for i in $var
     do
        p="$p
     $i"       # New line directly in the source code
     done
     echo "$p" # Double quotes required
               # But -e not required
    

    Avoid extra leading newline

     var="a b c"
     first_loop=1
     for i in $var
     do
        (( $first_loop )) &&  # "((...))" is Bash specific
        p="$i"            ||  # First -> Set
        p="$p
     $i"                      # After -> Append
        unset first_loop
     done
     echo "$p"                # No need -e
    

    Using a function

     embed_newline()
     {
        local p="$1"
        shift
        for i in "$@"
        do
           p="$p
     $i"                      # Append
        done
        echo "$p"             # No need -e
     }
    
     var="a b c"
     p=$( embed_newline $var )  # Do not use double quotes "$var"
     echo "$p"
    
  3. Using $'\n' (less portable)

    and interprets $'\n' as a new line.

     var="a b c"
     for i in $var
     do
        p="$p"$'\n'"$i"
     done
     echo "$p" # Double quotes required
               # But -e not required
    

    Avoid extra leading newline

     var="a b c"
     first_loop=1
     for i in $var
     do
        (( $first_loop )) &&  # "((...))" is bash specific
        p="$i"            ||  # First -> Set
        p="$p"$'\n'"$i"       # After -> Append
        unset first_loop
     done
     echo "$p"                # No need -e
    

    Using a function

     embed_newline()
     {
        local p="$1"
        shift
        for i in "$@"
        do
           p="$p"$'\n'"$i"    # Append
        done
        echo "$p"             # No need -e
     }
    
     var="a b c"
     p=$( embed_newline $var )  # Do not use double quotes "$var"
     echo "$p"
    

The output is the same for all

a
b
c

Special thanks to contributors of this answer: kevinf, Gordon Davisson, l0b0, Dolda2000 and tripleee.


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