A string of strings is different than a table or matrix of strings. String of Strings Let a string be one or more sequential characters, such as “first”. A string may contain another string or commonly known as a substring. The string “theater” contains at least the strings “the”, “eat”, and “ate”. Matrix of Strings … Read more
What is a copy constructor? Quoting the C++11 standard, §12.8/2: “A non-template constructor for class X is a copy constructor if its first parameter is of type X&, const X&, volatile X& or const volatile X&, and either there are no other parameters or else all other parameters have default arguments” So there are 4 … Read more
You can use Dynamic Programming for this task: f(0) = 0 f(i) = MIN { f(i-j) + (Dictionary.contais(s.substring(i-j,i)?1:INFINITY } for each j=1,…,i The above finds the number of words in your string, so the final answer is f(#characters)-1 The idea is to do an “exhaustive search” – for a given new character – try to … Read more
No you can’t. The protected accessor on a method means that only the following can access it: the class itself class that inherits from it another class with friendship https://en.cppreference.com/w/cpp/language/access#Protected_member_access
Your else statement is a call to isdigit function, and you discard the result. The block statement that follows is outside of the if-else statement (whose if part isn’t shown) and is thus executed regardless of that condition (which isn’t shown). else will be executed and check if it is a number if it is … Read more
—————- Edit —————- I completely missed that you need to output the positive integers as well.. In that case, take a look at std::vector where you would add these integers, and then you would iterate through them using a for loop again. Or, you could also print them out right away.. Since this is apparently … Read more
int function(int a, int b){ // two variables, a and b, are declared and set equal to whatever you passed in when you called the function. a = a*b; // now you are using the two already-declared variables return(a); // return the value of ‘a’ which was declared in the first line and then modified … Read more
The pre-conditions of the printf function require that you pass a data pointer as an argument to %p – and more specifically, a pointer of type void*. obj1 is not a data pointer; it is an instance of issue. The behaviour of violating the pre-conditions of printf is undefined. obj1.issue_c2 is a pointer, but it … Read more
You can’t use the !Val condition: const char* Val = va_arg(ArgList, const char*); if (!Val) break; When using variable argument list you need to know exactly how many arguments have been passed, or (update) when to stop processing the arguments, using e.g. NULL / nullptr (or any other) sentinel.
Not likely to be your crash, but this code is terrible: if (fnameFile.is_open()) { while (fnameFile.eof() == false) { plFname.resize(numFnames); getline(fnameFile,line); numFnames += 1; } fnameFile.close(); } It doesn’t check for end of file correctly, because end of file happens during getline, not before. And the line variable goes nowhere. Try while (getline(fnameFile,line)) plFnames.push_back(line); fnameFile.close();