What is short-circuit evaluation in C?

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The && operator uses lazy evaluation. If either side of the && operator is false, then the whole expression is false.

C checks the truth value of the left hand side of the operator, which in your case is 0. Since 0 is false in c, then the right hand side expression of the operation, (a = b = 777), is never evaluated.

The second case is similar, except that || returns true if the left hand side expression returns true. Also remember that in c, anything that is not 0 is considered true.

Hope this helps.

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