A struct cannot be empty in C because the syntax forbids it. Furthermore, there is a semantic constraint that makes behavior undefined if a struct has no named member:
struct-or-union-specifier:
struct-or-union identifieropt { struct-declaration-list }
struct-or-union identifier
struct-or-union:
struct
union
struct-declaration-list:
struct-declaration
struct-declaration-list struct-declaration
struct-declaration:
specifier-qualifier-list struct-declarator-list ;
/* type-specifier or qualifier required here! */
specifier-qualifier-list:
type-specifier specifier-qualifier-listopt
type-qualifier specifier-qualifier-listopt
struct-declarator-list:
struct-declarator
struct-declarator-list , struct-declarator
struct-declarator:
declarator
declaratoropt : constant-expression
If you write
struct identifier { };
It will give you a diagnostic message, because you violate syntactic rules. If you write
struct identifier { int : 0; };
Then you have a non-empty struct with no named members, thus making behavior undefined, and not requiring a diagnostic:
If the struct-declaration-list contains no named members, the behavior is undefined.
Notice that the following is disallowed because a flexible array member cannot be the first member:
struct identifier { type ident[]; };