Why doesn’t scanf need an ampersand for strings and also works fine in printf (in C)?

by

scanf needs the address of the variable to read into, and string buffers are already represented as addresses (pointer to a location in memory, or an array that decomposes into a pointer).

printf does the same, treating %s as a pointer-to-string.

More Related Contents:

  1. How do you allow spaces to be entered using scanf?
  2. How do you type something on the same line of text in C [closed]
  3. What is the output of the following code in C? [closed]
  4. ‘ ‘, ‘\n’ , scanf() and output screen
  5. decimal of numbers in c
  6. pointer to string concept in c [closed]
  7. Segmentation fault using scanf() [closed]
  8. C prog. Pointers and strings [closed]
  9. How to use sscanf in loops?
  10. What does sizeof(&array) return?
  11. When should I use ampersand with scanf()
  12. Using the equality operator == to compare two strings for equality in C [duplicate]
  13. printf(“%p”) and casting to (void *)
  14. Reading string from input with space character? [duplicate]
  15. Modifying C string constants? [duplicate]
  16. using scanf(“%d “) with a space after the %d
  17. Reversing a string in C
  18. Read no more than size of string with scanf()
  19. printf not printing on console
  20. C – Difference between “char var[]” and “char *var”?
  21. Reading a string with spaces with sscanf
  22. How to format strings using printf() to get equal length in the output
  23. using printf to print out floating values
  24. Literal string initializer for a character array
  25. Wrong format specifiers in scanf (or) printf
  26. Segmentation fault occurring when modifying a string using pointers?
  27. Using printf with a non-null terminated string
  28. Does C have a string type? [closed]
  29. Strange character after an array of characters
  30. What is the difference between %f and %lf in C?

Leave a Comment