Why is 09 “too large” of an integer number? [duplicate]

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Numbers beginning with 0 are considered octal – and 9 is not an octal digit (but (conventionally) 0-7 are).

Hexadecimal literals begin with 0x, e.g. 0xA.

Up until Java 6, there was no literal notation for binary and
you’ll had to use something like 

int a = Integer.parseInt("1011011", 2);

where the second argument specifies the desired base.

Java 7 now has binary literals.

In Java SE 7, the integral types (byte, short, int, and long) can also be expressed using the binary number system. To specify a binary literal, add the prefix 0b or 0B to the number.

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