Yes, they can. Starting with C++23 you can use the explicit this parameter:
auto factorial = [](this auto self, int i)
{
return (i == 1) ? 1 : i * self(i - 1);
};
With previous C++ standards, you can store the lambda in a variable and reference that variable (although you cannot declare the type of that variable as auto
, you would have to use an std::function
object instead). For instance:
std::function<int (int)> factorial = [&] (int i)
{
return (i == 1) ? 1 : i * factorial(i - 1);
};