The construct of INDEX()
>>:
<<INDEX()
will work when applied to ranges. Not to arrays AFAIK. It will lead to these errors. Maybe try something like:
=LET(range,A1:D2,MAKEARRAY(ROWS(range),COLUMNS(range),LAMBDA(r,c,SUM(INDEX(range,r,SEQUENCE(c))))))
This would resemble the construct of your inital formula. However, in the linked question you have mentioned that you’d like to use SCAN()
in combination with BYROW()
. You have noticed that nesting these lambda helper functions will result in an error. I just wanted to show you that it is possible with just a single SCAN()
function:
=SCAN(0,A1:D2,LAMBDA(a,b,IF(COLUMN(b)=1,b,a+b)))
Or even less verbose:
=SCAN(0,A1:D2,LAMBDA(a,b,a*(COLUMN(b)<>1)+b))
I have been puzzling a bit and found that we could compare the row/column of the ‘b’ variable inside the lambda structure. Something I haven’t been aware of prior to….now. It does feel a bit glitchy but now we can actually use some sort of variation to the BYROW()
helper inside SCAN()
and do these calculation for each row of the intial array seperately.