This is the expected behaviour, and I’ve explained this before in this answer (not a duplicate, though).
What happened is that Mike Bostock, D3 creator, introduced a magic behaviour in D3 v2, which he kept in D3 v3.x, but decided to abandon in D3 v4.x. To read more about that, have a look here: What Makes Software Good? This is what he says:
D3 2.0 introduced a change: appending to the enter selection would now copy entering elements into the update selection […] D3 4.0 removes the magic of enter.append. (In fact, D3 4.0 removes the distinction between enter and normal selections entirely: there is now only one class of selection.)
Let’s see it.
Here is your code with D3 v3:
var svg = d3.select('body').append('svg')
.attr('width', 250)
.attr('height', 250);
//render the data
function render(data) {
//Bind
var circles = svg.selectAll('circle').data(data);
//Enter
circles.enter().append('circle')
.attr('r', 10);
//Update
circles
.attr('cx', function(d) {
return d.x;
})
.attr('cy', function(d) {
return d.y;
});
//Exit
circles.exit().remove();
}
var myObjects = [{
x: 100,
y: 100
}, {
x: 130,
y: 120
}, {
x: 80,
y: 180
}, {
x: 180,
y: 80
}, {
x: 180,
y: 40
}];
render(myObjects);
<script src="https://d3js.org/d3.v3.min.js"></script>
Now the same code, with D3 v4. It will “break”:
var svg = d3.select('body').append('svg')
.attr('width', 250)
.attr('height', 250);
//render the data
function render(data) {
//Bind
var circles = svg.selectAll('circle').data(data);
//Enter
circles.enter().append('circle')
.attr('r', 10);
//Update
circles
.attr('cx', function(d) {
return d.x;
})
.attr('cy', function(d) {
return d.y;
});
//Exit
circles.exit().remove();
}
var myObjects = [{
x: 100,
y: 100
}, {
x: 130,
y: 120
}, {
x: 80,
y: 180
}, {
x: 180,
y: 80
}, {
x: 180,
y: 40
}];
render(myObjects);
<script src="https://d3js.org/d3.v4.min.js"></script>
By “break” I mean the circles will be appended, but they will not receive the x
and y
properties in the “enter” selection, and they will default to zero. That’s why you see all circles at the top left corner.
Solution: merge the selections:
circles.enter().append('circle')
.attr('r', 10)
.merge(circles) //from now on, enter + update
.attr('cx', function(d) {
return d.x;
})
.attr('cy', function(d) {
return d.y;
});
According to the API, merge()
…
… is commonly used to merge the enter and update selections after a data-join. After modifying the entering and updating elements separately, you can merge the two selections and perform operations on both without duplicate code.
Here is the code with merge()
:
var svg = d3.select('body').append('svg')
.attr('width', 250)
.attr('height', 250);
//render the data
function render(data) {
//Bind
var circles = svg.selectAll('circle').data(data);
//Enter
circles.enter().append('circle')
.attr('r', 10)
.merge(circles) //from now on, enter + update
.attr('cx', function(d) {
return d.x;
})
.attr('cy', function(d) {
return d.y;
});
//Exit
circles.exit().remove();
}
var myObjects = [{
x: 100,
y: 100
}, {
x: 130,
y: 120
}, {
x: 80,
y: 180
}, {
x: 180,
y: 80
}, {
x: 180,
y: 40
}];
render(myObjects);
<script src="https://d3js.org/d3.v4.min.js"></script>