Line 11 is
p1 = &a;
where p1
has type int **
and a
has type int[3]
, right?
Well; &a
has type int(*)[3]
and that type is not compatible with int**
as the compiler told you
You may want to try
p1 = &p0;
And read the c-faq, particularly section 6.
In short: arrays are not pointers, and pointers are not arrays.