echo “-e” doesn’t print anything

by

The one true way to print any arbitrary string:

printf "%s" "$vars"

More Related Contents:

  1. What does 2>&1 mean here?
  2. How to reload .bashrc settings without logging out and back in again?
  3. How do I iterate over a range of numbers defined by variables in Bash?
  4. When do we need curly braces around shell variables?
  5. How to manually expand a special variable (ex: ~ tilde) in bash
  6. Accessing bash command line args $@ vs $*
  7. Bash command line and input limit
  8. Replace one substring for another string in shell script
  9. How can I escape a double quote inside double quotes?
  10. Tilde in path doesn’t expand to home directory
  11. When are square brackets required in a Bash if statement?
  12. Bash syntax error: unexpected end of file
  13. How to assign the output of a Bash command to a variable? [duplicate]
  14. Is there a TRY CATCH command in Bash
  15. Parsing variables from config file in Bash
  16. Bash check shows file exists for non-existent files?
  17. Bash variables with spaces
  18. find: missing argument to -exec
  19. Retrieving multiple arguments for a single option using getopts in Bash
  20. grep for expression containing variable
  21. Connect to sqlplus in a shell script and run SQL scripts
  22. How do I pass on script arguments that contain quotes/spaces?
  23. Convert seconds to hours, minutes, seconds
  24. How to check if running as root in a bash script
  25. Print a file’s last modified date in Bash
  26. How to escape the single quote character in an ssh / remote bash command?
  27. Returning a boolean from a Bash function
  28. Capture multiline output as array in bash [duplicate]
  29. Parallel wget in Bash [duplicate]
  30. for loop for multiple extension and do something with each file

Leave a Comment