Excel-VBA – Insert new first column in datafield array without loops or API calls

Found solution via the Application.Index function

I found a solution simply by trying out some unusual variations of the Application.Index function which I try to resume as a comprehensive generic overview to demonstrate the rich range of application. So any helpful addition is welcome (c.f. @chrisneilsen ‘s comment).

Some peculiarities of the the Application.Index function

Typically the index function would deliver a well defined item by its row and column position, but there are some not so widely known pecularities:

  1. Similarly to the Worksheet.Index function you can get the entire column or row items if the row or column number argument is set to zero (0). – Another frequently unknown way to create a 2-dim array by passing a double-zero parameter can be found at How to initialize a 2-dim array in Excel VBA

  2. Use of array arguments possible – This function allows not only the known index indications by given numbers, but also array parameters to extract “rows” or “columns”, so it’s possible to indicate a wanted set of columns, e.g.A:C via Array(1,2,3) as column array argument.

  3. Filtering effects – Furthermore I learnt that it is possible to reduce the choice to some columns (rows) only, e.g. via Array(1,3) and even to change the internal order, e.g. Array(3,2,1)`.

  4. Restructuring – The most surprising fact, however, is that it is possible to repeat a column choice, e.g. via Array(1,1,2,3)
    or even Array(0,1,2,3) where the 0 item is the same as column 1. This can be used to reach the same effect as a column insertion.

This last restructuring capability of the mentioned Index function is the key part of my approach:

Code example

Sub AddFirstIndexColumn()
  Dim v, i&, ws As Worksheet
  Set ws = ThisWorkbook.Worksheets("SourceSheet")  ' << change to source sheet name
' [1] get data
      v = ws.[A1:C5].Value2
' [2] define column array inserting first column (0 or 1) and preserving old values (1,2,3)
      v = Application.Index(v, _
          Application.Evaluate("row(1:" & UBound(v) & ")"), _
          Array(0, 1, 2, 3))   ' columns array where 0 reinserts the first column
' [3] add an current number in the first column
      For i = LBound(v) To UBound(v): v(i, 1) = i: Next i
 End Sub

How to test the result

Just insert the following to the code above:

' [4a] test result by debugging in immediate window
      For i = LBound(v) To UBound(v)
          Debug.Print "#" & i & ": " & Join(Application.Index(v, i, 0), ", ")
      Next i
' [4b] test result by writing back to target sheet
      Dim ws2 As Worksheet
      Set ws2 = ThisWorkbook.Worksheets("TargetSheet")  ' << change to target sheet name
      ws2.Range("A1").Resize(UBound(v), UBound(v, 2)).Offset(0, 0) = v

Caveat

The found solution seems to be restricted to 65536 rows (possibly similar to array transposing limitation), so that you can’t use it for bigger data.

Some recent Application.Index examples

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