Fire local notification every day on different times

According to Apple documentation:

An application can have only a limited number of scheduled notifications; the system keeps the soonest firing 64 notifications (with automatically rescheduled notifications counting as a single notification) and discards the rest

I solved that problem by setting a “queue” of notifications. For example, in my app I have three different types of notifications, let’s just say type A, B and C.

I schedule the A, B and C notifications for the next month, everytime the user opens the app, I checked how many notifications left. If, for example, the are no more A notifications, the app schedules more A notifications and so on.

How I achieve this?

Everytime I schedule a notification, I use the userInfo property. I set a dictionary with a key called type and a value.

In my app delegate I check all the pending notifications and count how many left for each type. The code looks like this:

NSArray *scheduledNotifications = [UIApplication scheduledLocalNotifications];

NSUInteger AType, BType, CType;

for (UILocalNotification *notif in scheduledNotifications) {
        //Classify notifications by type
        NSUInteger notifType = [[notif.userInfo objectForKey:@"type"]integerValue];
        if (notifType == 0) {
           AType++;
        }else if(notifType == 1){
            BType++;
        }else{
            CType++;
        }

}

If the count of any type is zero the app schedules more notifications.

Finally, if the notifications are show for example, everyday at the same hour you can use the repeatInterval property BUT you can’t create your own repeating intervals, you can only use the repeating intervals defined in NSCalendarUnit.

Hope it helps.