Get the application’s path

by

In Java the calls

System.getProperty("user.dir")

and

new java.io.File(".").getAbsolutePath();

return the current working directory.

The call to 

getClass().getProtectionDomain().getCodeSource().getLocation().getPath();

returns the path to the JAR file containing the current class, or the CLASSPATH element (path) that yielded the current class if you’re running directly from the filesystem.

Example:

  1. Your application is located at 

     C:\MyJar.jar

  2. Open the shell (cmd.exe) and cd to C:\test\subdirectory.

  3. Start the application using the command java -jar C:\MyJar.jar.

  4. The first two calls return ‘C:\test\subdirectory’; the third call returns ‘C:\MyJar.jar’.

When running from a filesystem rather than a JAR file, the result will be the path to the root of the generated class files, for instance

c:\eclipse\workspaces\YourProject\bin\

The path does not include the package directories for the generated class files.

A complete example to get the application directory without .jar file name, or the corresponding path to the class files if running directly from the filesystem (e.g. when debugging):

String applicationDir = getClass().getProtectionDomain().getCodeSource().getLocation().getPath(); 

if (applicationDir.endsWith(".jar"))
{
    applicationDir = new File(applicationDir).getParent();
}
// else we already have the correct answer

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