Get the calling function name from the called function [duplicate]

by 
new StackFrame(1, true).GetMethod().Name

Note that in release builds the compiler might inline the method being called, in which case the above code would return the caller of the caller, so to be safe you should decorate your method with:

[MethodImpl(MethodImplOptions.NoInlining)]

More Related Contents:

  1. LINQ query on a DataTable
  2. Creating a DateTime in a specific Time Zone in c#
  3. How can I convert an integer into its verbal representation?
  4. Workaround for lack of ‘nameof’ operator in C# for type-safe databinding?
  5. How to change the color of progressbar in C# .NET 3.5?
  6. Should functions return null or an empty object?
  7. How to parse a string into a nullable int
  8. Don’t stop debugger at THAT exception when it’s thrown and caught
  9. Inconsistency in divide-by-zero behavior between different value types
  10. Why C# is not allowing non-member functions like C++
  11. Software rendering mode – WPF
  12. What is the Efficiency and Performance of LINQ and Lambda Expression in .Net?
  13. Operation could destabilize the runtime?
  14. Monitoring Garbage Collector in C#
  15. How do I get the Local Network IP address of a computer programmatically?
  16. Is it possible to intercept Console output?
  17. How can I join int[] to a character-separated string in .NET?
  18. Dependency Injection wcf
  19. Put WPF control into a Windows Forms Form?
  20. Finding all classes with a particular attribute
  21. Replacing a DataReader with a DataTable
  22. How do I compile my App.config into my exe in a VS2010 C# console app?
  23. Get first element from a dictionary
  24. Using conditional (?:) operator for method selection in C# (3.0)?
  25. How to check if process is not responding?
  26. Stack capacity in C#
  27. Regular Expression for password validation
  28. LINQ: Add RowNumber Column
  29. Authentication Service using WCF
  30. The ObjectContext instance has been disposed and can no longer be used for operations that require a connection [duplicate]

Leave a Comment