Unfortunately, it isn’t possible.
Not even with a helper method. The helper method has the same problems as your second attempt: this
is of type B
, even in the base class and will call the implementation of M
in B
:
interface I
{
int M();
}
class A : I
{
int I.M() { return 1; }
protected int CallM() { return (this as I).M(); }
}
class B : A, I
{
int I.M() { return CallM(); }
}
The only workaround would be a helper method in A
that is used in A
‘s implementation of M
:
interface I
{
int M();
}
class A : I
{
int I.M() { return CallM(); }
protected int CallM() { return 1; }
}
class B : A, I
{
int I.M() { return CallM(); }
}
But you would need to provide a method like this also for B
if there will be a class C : B, I
…