How to print function pointers with cout?

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There actually is an overload of the << operator that looks something like:

ostream & operator <<( ostream &, const void * );

which does what you expect – outputs in hex. There can be no such standard library overload for function pointers, because there are infinite number of types of them. So the pointer gets converted to another type, which in this case seems to be a bool – I can’t offhand remember the rules for this.

Edit: The C++ Standard specifies:

4.12 Boolean conversions

1 An rvalue of arithmetic,
enumeration, pointer, or pointer to
member type can be converted to an
rvalue of type bool.

This is the only conversion specified for function pointers.

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