int val = -32768;
String hex = Integer.toHexString(val);
int parsedResult = (int) Long.parseLong(hex, 16);
System.out.println(parsedResult);
That’s how you can do it.
The reason why it doesn’t work your way: Integer.parseInt
takes a signed int, while toHexString
produces an unsigned result. So if you insert something higher than 0x7FFFFFF
, an error will be thrown automatically. If you parse it as long
instead, it will still be signed. But when you cast it back to int, it will overflow to the correct value.