Launch Program with Parameters

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You can use the ProcessStartInfo.Arguments property to specify the string of arguments for your program:

ProcessStartInfo startInfo = new ProcessStartInfo();        
startInfo.FileName = @"C:\etc\Program Files\ProgramFolder\Program.exe";
startInfo.Arguments = @"C:\etc\desktop\file.spp C:\etc\desktop\file.txt";
Process.Start(startInfo);

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