Parsing a Hexadecimal String to an Integer throws a NumberFormatException?

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Will this help?

Integer.parseInt("00ff00", 16)

16 means that you should interpret the string as 16-based (hexadecimal). By using 2 you can parse binary number, 8 stands for octal. 10 is default and parses decimal numbers.

In your case Integer.parseInt(primary.getFullHex(), 16) won’t work due to 0x prefix prepended by getFullHex() – get rid of and you’ll be fine.

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