Parsing field name with a colon in JSON

by

Using Json.Net

string json = @"{
            ""dc:creator"":""Jordan, Micheal"",
            ""element:publicationName"":""Applied Ergonomics"",
            ""element:issn"":""2839749823""
        }";

var pub = JsonConvert.DeserializeObject<Publication>(json);

public class Publication
{
    [JsonProperty("dc:creator")]
    public string creator { set; get; }
    [JsonProperty("element:publicationName")]
    public string publicationName { set; get; }
    [JsonProperty("element:issn")]
    public string issn { set; get; }
}

OR

Console.WriteLine(JObject.Parse(json)["dc:creator"]);

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