What I don’t understand is what happens when I invoke a method, what actually happens. Does new() get invoked? Does it just automagically copy the data? Or does it actually just point to the original object? And how does using ref and out affect this?
The short answer:
The empty constructor will not be called automatically, and it actually just points to the original object.
using ref and out does not affect this.
The long answer:
I think it would be easier to understand how C# handles passing arguments to a function.
Actually everything is being passed by value
Really?! Everything by value?
Yes! Everything!
Of course there must be some kind of a difference between passing classes and simple typed objects, such as an Integer, otherwise, it would be a huge step back performance wise.
Well the thing is, that behind the scenes when you pass a class instance of an object to a function, what is really being passed to the function is the pointer to the class. the pointer, of course, can be passed by value without causing performance issues.
Actually, everything is being passed by value; it’s just that when
you’re “passing an object”, you’re actually passing a reference to that
object (and you’re passing that reference by value).
once we are in the function, given the argument pointer, we can relate to the object passed by reference.
You don’t actually need to do anything for this, you can relate directly to the instance passed as the argument (as said before, this whole process is being done behind the scenes).
After understanding this, you probably understand that the empty constructor will not be called automatically, and it actually just points to the original object.
EDITED:
As to the out and ref, they allow functions to change the value of an arguments and have that change persist outside of the scope of the function.
In a nutshell, using the ref keyword for value types will act as follows:
int i = 42;
foo(ref i);
will translate in c++ to:
int i = 42;
int* ptrI = &i;
foo(ptrI)
while omitting the ref will simply translate to:
int i = 42;
foo(i)
using those keywords for reference type objects, will allow you to reallocate memory to the passed argument, and make the reallocation persist outside of the scope of the function (for more details please refer to the MSDN page)
Side note:
The difference between ref and out is that out makes sure that the called function must assign a value to the out argument, while ref does not have this restriction, and then you should handle it by assigning some default value yourself, thus, ref Implies the the initial value of the argument is important to the function and might affect it’s behaviour.