removing invalid XML characters from a string in java

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Java’s regex supports supplementary characters, so you can specify those high ranges with two UTF-16 encoded chars.

Here is the pattern for removing characters that are illegal in XML 1.0:

// XML 1.0
// #x9 | #xA | #xD | [#x20-#xD7FF] | [#xE000-#xFFFD] | [#x10000-#x10FFFF]
String xml10pattern = "[^"
                    + "\u0009\r\n"
                    + "\u0020-\uD7FF"
                    + "\uE000-\uFFFD"
                    + "\ud800\udc00-\udbff\udfff"
                    + "]";

Most people will want the XML 1.0 version.

Here is the pattern for removing characters that are illegal in XML 1.1:

// XML 1.1
// [#x1-#xD7FF] | [#xE000-#xFFFD] | [#x10000-#x10FFFF]
String xml11pattern = "[^"
                    + "\u0001-\uD7FF"
                    + "\uE000-\uFFFD"
                    + "\ud800\udc00-\udbff\udfff"
                    + "]+";

You will need to use String.replaceAll(...) and not String.replace(...).

String illegal = "Hello, World!\0";
String legal = illegal.replaceAll(pattern, "");

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