Below, I have written an answer for n equals to 5, but you can apply same approach to draw DFAs for any value of n and ‘any positional number system’ e.g binary, ternary… First lean the term ‘Complete DFA’, A DFA defined on complete domain in δ:Q × Σ→Q is called ‘Complete DFA’. In other … Read more
Yes, it turns out this does exist; what is required is what is known academically as a DFA Learning algorithm, examples of which include: Angluin’s L* L* (adding counter-examples to columns) Kearns / Vazirani Rivest / Schapire NL* Regular positive negative inference (RPNI) DeLeTe2 Biermann & Feldman’s algorithm Biermann & Feldman’s algorithm (using SAT-solving) Source … Read more
Regular grammar is either right or left linear, whereas context free grammar is basically any combination of terminals and non-terminals. Hence you can see that regular grammar is a subset of context-free grammar. So for a palindrome for instance, is of the form, S->ABA A->something B->something You can clearly see that palindromes cannot be expressed … Read more
“IN CONTEXT OF CHOMSHY CLASSIFICATION OF FORMAL LANGUAGE” (1) L3 = {wwR | w ∈ {a, b}* } Language L3 is a Non-Deterministic Context Free Language, its also Unambiguous and Liner language. (2) Lp is language of parenthesis matching. There are two terminal symbols “(” and “)”. Grammar for Lp is: S → SS S … Read more
As you says in question: I know that to convert a DFA, M to the complement, M`, I just need to swap the initial accepting states and final accepting states. Its not complement, but you are doing something like reverse of a language and regular languages are closure under reversal. Reversal of DFA What is … Read more
Yes, it is possible, we can generate regexes from examples (text -> desired extractions). This is a working online tool which does the job: http://regex.inginf.units.it/ Regex Generator++ online tool generates a regex from provided examples using a GP search algorithm. The GP algorithm is driven by a multiobjective fitness which leads to higher performance and … Read more
The * at the end can be taken to mean the initial state is accepting and that the automaton returns to this state whenever it accepts anything. Call the initial state q1. To accept 1(01*0)1 we must first consume a 1 and go to a new state, say q2. From there, we can self-loop on … Read more