To answer your question directly, put r in front of the string. final= path + r’\xulrunner.exe ‘ + path + r’\application.ini’ But a better solution would be os.path.join: final = os.path.join(path, ‘xulrunner.exe’) + ‘ ‘ + \ os.path.join(path, ‘application.ini’) (the backslash there is escaping a newline, but you could put the whole thing on one … Read more
You need to escape your backslash by preceding it with, yes, another backslash: print(“\\”) And for versions prior to Python 3: print “\\” The \ character is called an escape character, which interprets the character following it differently. For example, n by itself is simply a letter, but when you precede it with a backslash, … Read more
Don’t use String.replaceAll in this case – that’s specified in terms of regular expressions, which means you’d need even more escaping. This should be fine: String escaped = original.replace(“\\”, “\\\\”); Note that the backslashes are doubled due to being in Java string literals – so the actual strings involved here are “single backslash” and “double … Read more
Double-quoted strings support the full range of escape sequences, as shown below: \a Bell/alert (0x07) \b Backspace (0x08) \e Escape (0x1b) \f Formford (0x0c) \n Newline (0x0a) \r Return (0x0d) \s Space (0x20) \t Tab (0x09) \v Vertical tab (0x0b) For single-quoted strings, two consecutive backslashes are replaced by a single backslash, and a backslash … Read more
Use a double slash in Java string literal to escape a slash : String s = “c:\\new folder\\title.csv”; If an end user enters a string in a JFileChooser, the string variable will contain all the characters entered by the user. Escaping is only needed when using String literals in Java source code. And use a … Read more
Quick Answer If you want to sidestep all this confusion, use the much less confusing block syntax. Here is an example that replaces each backslash with 2 backslashes: “some\\path”.gsub(‘\\’) { ‘\\\\’ } Gruesome Details The problem is that when using sub (and gsub), without a block, ruby interprets special character sequences in the replacement parameter. … Read more
Do it like that: a, b, c, d = range(1, 5) result = ( # First is 1 a * # Then goes 2, result is 2 now b * # And then 3, result is 6 c * # And 4, result should be 24 d ) Actually, according to PEP8 parentheses are preferred … Read more
I found a solution that works str = gsub(“([\\])”,””, str)
The backslash before the semicolon is used, because ; is one of list operators (or &&, ||) for separating shell commands. In example: command1; command2 The find utility is using ; or + to terminate the shell commands invoked by -exec. So to avoid special shell characters from interpretation, they need to be escaped with … Read more
replace all the \ with \\. it’s trying to escape the next character in this case the U so to insert a \ you need to insert an escaped \ which is \\