Got stumped by this for ages and all the answers kept insisting that the source string needs to already have escaped backslashes in it … which isn’t always the case. Do this .. var replaced = str.replace(String.fromCharCode(92),String.fromCharCode(92,92));
For security reasons, it is not possible to get the real, full path of a file, referred through an <input type=”file” /> element. This question already mentions, and links to other Stack Overflow questions regarding this topic. Previous answer, kept as a reference for future visitors who reach this page through the title, tags and … Read more
First and foremost, replacement patterns ≠ regular expression patterns We use a regex pattern to search for matches, we use replacement patterns to replace matches found with regex. NOTE: The only special character in a substitution pattern is a backslash, \. Only the backslash must be doubled. Replacement pattern syntax in Python The re.sub docs … Read more
No need to use str.replace or string.replace here, just convert that string to a raw string: >>> strs = r”C:\Users\Josh\Desktop\20130216″ ^ | notice the ‘r’ Below is the repr version of the above string, that’s why you’re seeing \\ here. But, in fact the actual string contains just ‘\’ not \\. >>> strs ‘C:\\Users\\Josh\\Desktop\\20130216’ >>> … Read more
/ is the path separator on Unix and Unix-like systems. Modern Windows can generally use both \ and / interchangeably for filepaths, but Microsoft has advocated for the use of \ as the path separator for decades. This is done for historical reasons that date as far back as the 1970s, predating Windows by over … Read more
I suspect your string already actually only contains a single backslash, but you’re looking at it in the debugger which is escaping it for you into a form which would be valid as a regular string literal in C#. If print it out in the console, or in a message box, does it show with … Read more
http://locutus.io/php/strings/addslashes/ function addslashes( str ) { return (str + ”).replace(/[\\”‘]/g, ‘\\$&’).replace(/\u0000/g, ‘\\0’); }
To answer your question directly, put r in front of the string. final= path + r’\xulrunner.exe ‘ + path + r’\application.ini’ But a better solution would be os.path.join: final = os.path.join(path, ‘xulrunner.exe’) + ‘ ‘ + \ os.path.join(path, ‘application.ini’) (the backslash there is escaping a newline, but you could put the whole thing on one … Read more
Yep, it’s exactly the same and this is the point of the backslash — it escapes the newline, allowing this long line to be split in two. An alternative is to use parentheses: from sqlalchemy.ext.declarative import (declarative_base, AbstractConcreteBase) While this is a syntax error: from sqlalchemy.ext.declarative import declarative_base, AbstractConcreteBase
The String#replaceAll() interprets the argument as a regular expression. The \ is an escape character in both String and regex. You need to double-escape it for regex: string.replaceAll(“\\\\”, “\\\\\\\\”); But you don’t necessarily need regex for this, simply because you want an exact character-by-character replacement and you don’t need patterns here. So String#replace() should suffice: … Read more