The range of double is way greater than the range of 32 or 64 bit integers, which is why std::floor returns a double. Casting to int should be fine so long as it’s within the appropriate range – but be aware that a double can’t represent all 64 bit integers exactly, so you may also … Read more
After a night lost trying to solve this problem I believe I’ve found a rather simple solution, here it is: function bcceil($number) { if (strpos($number, ‘.’) !== false) { if (preg_match(“~\.[0]+$~”, $number)) { return bcround($number, 0); } if ($number[0] != ‘-‘) { return bcadd($number, 1, 0); } return bcsub($number, 0, 0); } return $number; } … Read more
Since you’re looking for fourths (.00, .25, .50, .75), multiply your number by 4, round to nearest whole number as desired (floor if down, ceil if up), then divide by 4. 1.32, down to nearest fourth: 1.32 * 4 = 5.28 floor(5.28) = 5.00 5.00 / 4 = 1.25 Same principle applies for any other … Read more
Because, according to the ECMAScript specifications, bitwise operators operators call ToInt32 on each expression to be evaluated. See 11.10 Binary Bitwise Operators: The production A : A @B, where @ is one of the bitwise operators in the productions above, is evaluated as follows: Evaluate A. Call GetValue(Result(1)). Evaluate B. Call GetValue(Result(3)). Call ToInt32(Result(2)). Call … Read more
$seconds = time(); $rounded_seconds = round($seconds / (15 * 60)) * (15 * 60); echo “Original: ” . date(‘H:i’, $seconds) . “\n”; echo “Rounded: ” . date(‘H:i’, $rounded_seconds) . “\n”; This example gets the current time and rounds it to the nearest quarter and prints both the original and the rounded time. PS: If you … Read more