You can do it by finding unit vector of your line segment and scale it to your desired length, then translating end-point of your line segment with this vector. Assume your line segment end points are A and B and you want to extend after end-point B (and lenAB is length of line segment). #include … Read more
where P is the point, C is the center, and R is the radius, in a suitable “mathy” language: V = (P – C); Answer = C + V / |V| * R; where |V| is length of V. OK, OK double vX = pX – cX; double vY = pY – cY; double magV … Read more
I would suggest using the Path class from matplotlib import matplotlib.path as mplPath import numpy as np poly = [190, 50, 500, 310] bbPath = mplPath.Path(np.array([[poly[0], poly[1]], [poly[1], poly[2]], [poly[2], poly[3]], [poly[3], poly[0]]])) bbPath.contains_point((200, 100)) (There is also a contains_points function if you want to test for multiple points)
This is an 8-year-old question, but one that I recently struggled with, so I thought I’d share what I came up with. I spent a lot of time trying to use solution (9) from this article by Aleksas Riškus and couldn’t get any sensible numbers out of it until I did some Googling and learned … Read more
Lets do some maths my friend, as maths will always get to the end! Wikipedia: In mathematics, a Voronoi diagram is a partitioning of a plane into regions based on distance to points in a specific subset of the plane. For example: rng(1) x=rand(1,100)*5; y=rand(1,100)*5; voronoi(x,y); The nice thing about this diagram is that if … Read more
Using the Google Maps API V3, create a Circle object, then use bindTo() to tie it to the position of your Marker (since they are both google.maps.MVCObject instances). // Create marker var marker = new google.maps.Marker({ map: map, position: new google.maps.LatLng(53, -2.5), title: ‘Some location’ }); // Add circle overlay and bind to marker var … Read more
The simple equations from your link give the X and Y coordinates of the point on the circle relative to the center of the circle. X = r * cosine(angle) Y = r * sine(angle) This tells you how far the point is offset from the center of the circle. Since you have the coordinates … Read more
From the documentation for scatter: Optional kwargs control the Collection properties; in particular: edgecolors: The string ‘none’ to plot faces with no outlines facecolors: The string ‘none’ to plot unfilled outlines Try the following: import matplotlib.pyplot as plt import numpy as np x = np.random.randn(60) y = np.random.randn(60) plt.scatter(x, y, s=80, facecolors=”none”, edgecolors=”r”) plt.show() Note: … Read more
I found a way to accomplish this by joining the two data frames using a spatial join joinDF=gpd.sjoin(pointsDF, polysgdf, how=’left’,op=”within”)
SVG elliptic arcs are really tricky and took me a while to implement it (even following the SVG specs). I ended up with something like this in C++: //————————————————————————— class svg_usek // virtual class for svg_line types { public: int pat; // svg::pat[] index virtual void reset(){}; virtual double getl (double mx,double my){ return 1.0; … Read more