GL_POLYGON is only for convex polygons: GL_POLYGON: Draws a single, convex polygon. Vertices 1 through N define this polygon. For concave polygons you have at least two options: Triangulate the polygon and use GL_TRIANGLES. Use the stencil buffer trick.
JFrame does not have a paintComponent(Graphics g) method. Add the @Override annotation and you will get a compile time error. 1) Use JPanel and override paintComponent (you would than add JPanel to the JFrame viad JFrame#add(..)) 2) Override getPreferredSize() to return correct Dimensions which fit your drawing on Graphics object or else they wont be … Read more
If all you need is the coordinates here is a drawing tool I like to use – move the polygon or re-shape it and the coordinates will display right below the map: jsFiddle here. Also, here is a Codepen JS var bermudaTriangle; function initialize() { var myLatLng = new google.maps.LatLng(33.5190755, -111.9253654); var mapOptions = { … Read more
I would suggest using the Path class from matplotlib import matplotlib.path as mplPath import numpy as np poly = [190, 50, 500, 310] bbPath = mplPath.Path(np.array([[poly[0], poly[1]], [poly[1], poly[2]], [poly[2], poly[3]], [poly[3], poly[0]]])) bbPath.contains_point((200, 100)) (There is also a contains_points function if you want to test for multiple points)
Here you are. The interesting methods are getIntersections and getIntersection. The former parses over all polygon segments and checks for intersections, the latter does the actual calculation. Do keep in mind that the calculation can be seriously optimized and doesn’t check for division by 0. This will also work only for polygons. It could be … Read more
MySQL as of v5.1 only supports operations on the minimum bounding rectangles (MBR). While there is a “Contains” function which would do what you need, it is not fully implemented and falls back to using MBRContains From the relevant manual page Currently, MySQL does not implement these functions according to the specification. Those that are … Read more
It really is a matter of direction of indices in your polygons, while one is clockwise other should be counter-clockwise. Change your second array to: var circleOverlay = [ new google.maps.LatLng(25.774252, -80.190262), new google.maps.LatLng(32.321384, -64.75737), //second and third coordinates new google.maps.LatLng(18.466465, -66.118292), //are swapped compared to your original new google.maps.LatLng(25.774252, -80.190262) ]; and it will … Read more
Have been there 🙂 I also travelled through Stackoverflow’s PiP-suggestions, including your reference and this thread. Unfortunately, none of the suggestions (at least those I tried) were flawless and sufficient for a real-life scenario: like users plotting complex polygons on a Google map in freehand, “vicious” right vs left issues, negative numbers and so on. … Read more
The question by the OP is a bit ambiguous so the question I will answer is: How to generate a point from a uniform distribution within an arbitrary quadrilateral, which is actually a generalization of How to generate a point from a uniform distribution within an arbitrary (convex) polygon. The answer is based on the … Read more