You a looking for something like that? Option Explicit Public FromMacro As Boolean Sub X() FromMacro = True Call MacroX End Sub Sub MacroX() Dim Iteration As Long Dim i As Long If FromMacro = True Then Iteration = 1 Else Iteration = 100 End If For i = 1 To Iteration MsgBox Iteration Next … Read more
Iterative approach You can solve this by a simple iteration (Java): public static int T (int n) { if(n <= 0) { throw new IllegalArgumentException(“n must be larger or equal to one.”); } int result = 5; for(int i = 2; i <= n; i++) { result = result + 2*i; } return result; } … Read more
The mylist.index(“blah”) method of a list will return the index of the first occurrence of the item “blah”: >>> [“item 1”, “blah”, “item 3”].index(“blah”) 1 >>> [“item 1”, “item 2”, “blah”].index(“blah”) 2 It will raise ValueError if it cannot be found: >>> [“item 1”, “item 2”, “item 3”].index(“not found”) Traceback (most recent call last): File … Read more
As others have commented you probably have an iterator, not a list; You can use itertools.tee to get two independent iterators from same iterable: >>> from itertools import tee >>> a = [1, 2, 3] >>> fst, snd = tee(iter(a)) # two copies of same iterator >>> >>> list(fst) # exhaust the first iterator [1, … Read more
If you want a faster solution you can use itertools.repeat: from itertools import repeat: list(zip(repeat(0), range(101))) benchmark: %timeit [(0, x) for x in range(101)] # 3.64 µs ± 19.1 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each) %timeit list(zip(repeat(0), range(101))) # 2.81 µs ± 35.3 ns per loop (mean ± … Read more
In order to keep on adding the salary for each day and keeping the track of total for each day (as I get it from your statement), you can change:- total = amount * .01 * amount; to total += amount * .01 * amount; // total = total + (amount*0.01*amount) which(when not printing each … Read more
You can use a simple for-loop: document.write(“<h1>”); for (var i=namArLen-1; i>=0; i–) { document.write(namAr[i]); } document.write(“</h1>”); For simplicity, there’s also the reverse function on arrays: document.write(“<h1>”+namAr.reverse().join(“”)+”</h1>”);